X'd
- X'd的基本解釋
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[變形] x的過(guò)去分詞
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n.
字母x, 未知數(shù)
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adj.
X形的, X級(jí)的(電影等), 第二十四的
- 更多網(wǎng)絡(luò)例句與X'd相關(guān)的網(wǎng)絡(luò)例句 [注：此內(nèi)容來(lái)源于網(wǎng)絡(luò)在线AA亚洲视频，僅供參考]
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In Chapter 2, the D-symmetric solutions of matrix equation A~TXA = B on the linear manifold S ={X ∈ D~(-2)SR~|XZ = Y, Y = Y{D~2Z+D~2Z, Z~TD~2Y = Y~TD~2Z, Y,Z∈ R~}, by applying the generalized singular value decomposition of a matrix pair, the necessary and sufficient conditions for the existence and the expressions for the D-symmetric solutions of matrix equation A~TXA — B on the linear manifold are established.
運(yùn)用矩陣對(duì)的廣義奇異值分解，給出了這類線性流形上矩陣方程A~TXA=B存在D對(duì)稱解的充要條件及其通解的表達(dá)式色色色热。另外給出了它的D對(duì)稱最小二乘解的表達(dá)式久久香蕉不卡毛片。
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This is achieved by prefacing the member number with S, X, D or Z respectively.
這是通過(guò)與S作序的，十精品福利一区二区三区，分別為D或成員數(shù)目先锋影音资源在线。
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Tz = 2Gk q 即 z = 2Gk q /T 40 Suppose the volume between membrane and the boundary plane is V, and we notice that 2 ∫∫ d x d y = M Then we have Thereby we have q qM V =∫∫ zdxdy =∫∫ dxdy = 2GTk 4GTk M 2 Gk = 2V q /T From τ zx =τ xz =, y z 2Gk τ zx /= y q / T τ z y =τ yz = x 41 Moreover, we get 設(shè)薄膜及其邊界平面之間的體積為V,并注意到 2 ∫∫ d x d y = M 則有從而有由又可得 q qM V =∫∫ zdxdy =∫∫ dxdy = 2GTk 4GTk M 2 Gk = 2V q /T τ zx =τ xz =, y z 2Gk τ zx /= y q / T τ z y =τ yz = x 42 Adjust the pressure q of which the membrane is under, and make the rights of formulas,, equal to one, then we can gain some conclusions as follows:(1) The stress function of wringed pole equals to the uprightness angle of the membrane (2) The torsion M which wringed pole received equals to two times of the volume between the membrane and the boundary plane.
o b y a x 43 調(diào)整薄膜所受的壓力q，使得日日艹干日，95视频高潮喷水，三式等號(hào)的右邊為1，則可得出如下結(jié)論：(1)扭桿的應(yīng)力函數(shù)等于薄膜的垂度z特黄男女交性A片激情视频三。(2)扭桿所受的扭矩M等于該薄膜及其邊界平面之間的體積的兩倍国产麻豆精品二区无码专区。
- 更多網(wǎng)絡(luò)解釋與X'd相關(guān)的網(wǎng)絡(luò)解釋 [注：此內(nèi)容來(lái)源于網(wǎng)絡(luò)，僅供參考]
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